Perl:
($x, $y, $z) = "abc def ghi" =~ /^(.*?) (.*?) (.*?)$/;
Ruby:
(throwaway, x, y, z) = "abc def ghi".match(/^(.*?) (.*?) (.*?)$/).to_a
You know, sometimes, it’s just not the same.
Perl
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You could also do
x, y, z = "abc def ghi".scan(/^(.?) (.?) (.*?)$/)[0]By PatrickQG · 2007.02.16 00:08
I know. The point - and I’m not sure everyone gets that; I’m actually not sure anyone gets that, including me - the point is: If you look at Ruby’s =~, it returns the substring index. Perl, on the other hand, can return two different values depending on the context in which it’s called, scalar or list context. “Why would you ever want to do that?” is a common question whenever that ability comes up. This is the answer.
By Jesper · 2007.02.16 00:31
Yet another solution:
ruby -e ‘x, y, z = “abc def ghi”.match(/^(.*?) (.*?) (.*?)$/).captures; p x, y, z’
By Jon · 2007.02.17 18:12
Python:
import rematch = re.match('^(.*?) (.*?) (.*?)$', 'abc def ghi')
x, y, z = re.groups()
By Peter Hosey · 2007.02.18 07:09